Hello, Tony!
You should have been shown how to handle these . . .
The divisor must have a leading coefficient of 1.
. . If the leading coefficient isn't 1, divide through by it.
So we have: .
We will use for our divisor.
Important!
Since we are dividing by one-half of the given divisor,
. . the quotient will be twice as large as it should be.
We will make the adjustment at the end.
The synthetic division looks like this:
. . .
The bottom says: .
But the quotient is twice as large as it should be ... remember?
. . The remainder is unaffected.
Therefore, the answer is: .