Since it is constant over coefficient the possibilites are just the p factors over the q factors or in other words which is the same as
NOw to find which are roots put them in the original function!
I am sorry for mistyping it...but yeah none of them satisfy the conditions...so the conclusion in that there is no rational number which would make this polynomial equal to zero..
So does that mean, 1,2,4 are the possible rational roots but its possible that none of them would satisfy the condition?
Thanks once again!
I am sorry for misunderstanding again! For condition, I meant for the polynomial...when we plug all those possible rational numbers(1,4,2) we do not get zero in the polynomial equation...so does that mean there are no rational numbers which will satisfy this polynomial, like someone said at the first response above??