hi! is this correct???
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No, it's wrong, unless * is the symbol you use for the sum and + the one you use for the product...
Not it isn't. (I suppose it's n, not a) is equal to
The only thing you can do is to factor by , if :
Originally Posted by yuriythebest hi! is this correct??? no.....the only manipulation I could see would be this
and to test your hypothesis let a=2 and k=1 and n=2
wow thanks for the lighting-quick responses. But it seems I am still doing something terribly wrong:
I'd make a substitution :
Then the equation is now uČ+u=6
ok I tried it that way but it seems I am going around in circles...
No, you're not "going around in circles". Once you have found the two solutions of , you can solve for : and so on...
Be careful about
ok I tried that and got 2 negative roots:
OK you got the idea, now, read again the post #8. (especially the last sentence "Be careful...")
thank you flyingsquirrel! answer iz correct!
Originally Posted by yuriythebest thank you flyingsquirrel! answer iz correct! I'm referring to post #7: I don't understand where you've got the results from:
And therefore that means there doesn't exist a real x to satisfy this equation
yeah I understood that. cause of my spelling I mistook one of my u's for a 4 and therefore the incorrect answer. With your help I redid it and everything is correct.
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