how do you solve
3^(2x)-3^(x+2)+8=0
i think this needs a change of base on the 8
8 = 3^log.3. 8
in general
a^x = b^(log.b. a)(x)
move the term with the negative to the other side so they are all positive
then since you have all the numbers with base 3 you can say the bases are equal therefore the exponents must be equal
and then you can equate the exponents
i get x = 2 - log.3. 8