$2750 invested at 4.825% annual interest for 6 years compounded daily (n=365). find the amount that will be in the account given the stated conditions i cant figure this one out for the life of me
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Originally Posted by mattdale321 $2750 invested at 4.825% annual interest for 6 years compounded daily (n=365). i cant figure this one out for the life of me $\displaystyle p(t)=P_0(1+\frac{r}{n})^{nt}$ $\displaystyle P(6)=2750 \left(1+\frac{.04825}{365} \right)^{(365)(6)} \approx 3673.27$
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