x,y,z are different counting numbers.

What is the highest value for -2x-5y-3z

Results 1 to 5 of 5

- Apr 26th 2008, 01:30 PM #1

- Joined
- Apr 2008
- Posts
- 6

- Apr 26th 2008, 01:42 PM #2

- Joined
- Apr 2008
- Posts
- 1,092

- Apr 26th 2008, 01:47 PM #3

- Joined
- Apr 2008
- Posts
- 6

- Apr 26th 2008, 01:54 PM #4

- Joined
- Apr 2008
- Posts
- 1,092

Ok if the numbers need to be distinct, then you will obviously want to use the smallest numbers, which are 1, 2, and 3. Then substitute in the values for $\displaystyle x, y, z$ that make $\displaystyle -2x-5y-3z$ the closest to zero it can be. Since y has the highest coefficient, you want to put $\displaystyle y = 1$. Similarly, z has the next highest, so put $\displaystyle z = 2$, and finally $\displaystyle x = 3$. Then $\displaystyle -2(3)-5(1)-3(2) = -17.$

- Apr 26th 2008, 01:54 PM #5
The answer depends upon which side of the

*zero argument*you come down on.

Counting Number -- from Wolfram MathWorld

If zero is a counting number then the answer is –7. How?

If zero is not a counting number then what is the? Why?