I assume the aim of this exercise is to find h in terms of t then?h is inversely proportional to the third power of t and h=3/16 when t=4.
Do you divide the #'s? Multipy? I am completely confused.
So you know that h is inversely proportional to the third power of t.
What does that mean? Let's turn it from maths-speak into real words.
Well, it means that 1/h (the "inversely" bit) equals some number (call it k) times (the "proportional" bit) t^3 (the "third power of t" bit).
(By the way, if a is PROPORTIONAL to b, then a = some number times b.)
Now let's turn the real words back into maths again ;-)
1/h = k * t^3
Fantastic. Oh wait. We still need to know what k is. But we know that when t is 4, h is 3/16.
16/3 = k * (4)^3
You can use that to find k.
Then voila, you've got a relationship between h and t.
I hope this helps.