Thread: Brain Teaser #2

5.101001000100001....


he decimal number aboce consists of only one and 0 to the right of the decimal point. The first is followed by one 0, the second 1 is followed by two 0, the third 1 is followed by three 0 and so on. What is the total number of 0s between the 98th and the 101st 1 in this decimal number?


what i supposed was that 98th 1 has 98 0, and so on, thus i added up 98+99+100=297.... but for some reason the asnwer is 291. I need a good explanation, and some tips to solve number pattern problems and sequence problems. Thank you very much for your help!

Hello,

The n-th 1 is preceded by a number of 0 equal to

The p-th 1 is preceded by a number of 0 equal to

Hence, assuming that p>n, there is a number of 0 between the n-th and the p-th equal to :



This is the theorical part..

Here, p=101 and n=98... And I find the same result