What is the increase percentage from 48 to 18,000?

We had 48 people six years ago and now serving 18,000 people?

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- Apr 24th 2008, 11:46 AMLookin4AnswersIncrease Percentage
What is the increase percentage from 48 to 18,000?

We had 48 people six years ago and now serving 18,000 people? - Apr 24th 2008, 11:52 AMblair_alane
- Apr 24th 2008, 12:07 PMJhevon
in short:

$\displaystyle \mbox{Percent Change } = \frac {\mbox{New Amount}}{\mbox{Old Amount}} \times 100$

If the new amount is greater than the old amount, we have "Percent increase". if it is less, we have "Percent decrease"

So that here, $\displaystyle \mbox{Percentage Increase } = \frac {18000}{48} \times 100 = 37500$ % - Apr 24th 2008, 12:09 PMMoo
Hello,

I'd like to know why it is not :

$\displaystyle \text{New Amount}=\text{Old Amount}+100*\text{Increase Percentage}*\text{Old Amount}$

?

Quote:

well from the news i hear in the tele when they say increase in 200% it means the final value is double the original value. but percentage increase might just be an increment of that amount and not multiplication of that original amount

- Apr 24th 2008, 12:14 PMDanshader
well what i think is increment by x% means multiplication of the original value and increment of x% is additional of that increment to that original value.well i could be wrong thinking so o.o"

- Apr 24th 2008, 12:16 PMMoo
It seems that we're 4 thinking about it :/

- Apr 24th 2008, 12:42 PMJhevon
Yes, there are about two interpretations to this problem. i think it is up to the poster to let us know which he is after

- Apr 24th 2008, 02:02 PMblair_alane
I find it quite cool that everyone is so into this problem! :) hehe! Who knew? i feel like i started the trend! hehe!

Lookin4Answers, i hope you found your answers!

-BAM