# Increase Percentage

• Apr 24th 2008, 11:46 AM
Increase Percentage
What is the increase percentage from 48 to 18,000?

We had 48 people six years ago and now serving 18,000 people?
• Apr 24th 2008, 11:52 AM
blair_alane
Quote:

What is the increase percentage from 48 to 18,000?

We had 48 people six years ago and now serving 18,000 people?

hehe...so, like, I don't really know, but it could be 37400%.....is that what you're asking? I don't know so....don't take my word for it! :) hehe sorry if I'm wrong!

-BAM
• Apr 24th 2008, 12:07 PM
Jhevon
Quote:

What is the increase percentage from 48 to 18,000?

We had 48 people six years ago and now serving 18,000 people?

in short:

$\mbox{Percent Change } = \frac {\mbox{New Amount}}{\mbox{Old Amount}} \times 100$

If the new amount is greater than the old amount, we have "Percent increase". if it is less, we have "Percent decrease"

So that here, $\mbox{Percentage Increase } = \frac {18000}{48} \times 100 = 37500$ %
• Apr 24th 2008, 12:09 PM
Moo
Hello,

I'd like to know why it is not :

$\text{New Amount}=\text{Old Amount}+100*\text{Increase Percentage}*\text{Old Amount}$

?

Quote:

well from the news i hear in the tele when they say increase in 200% it means the final value is double the original value. but percentage increase might just be an increment of that amount and not multiplication of that original amount
• Apr 24th 2008, 12:14 PM
well what i think is increment by x% means multiplication of the original value and increment of x% is additional of that increment to that original value.well i could be wrong thinking so o.o"
• Apr 24th 2008, 12:16 PM
Moo
It seems that we're 4 thinking about it :/
• Apr 24th 2008, 12:42 PM
Jhevon
Yes, there are about two interpretations to this problem. i think it is up to the poster to let us know which he is after
• Apr 24th 2008, 02:02 PM
blair_alane
I find it quite cool that everyone is so into this problem! :) hehe! Who knew? i feel like i started the trend! hehe!