from n=1 to infinity of: (2n+n)/(5n^3 -1) Good luck!!! I hate these
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Is it $\displaystyle \sum\frac{2n+n}{5n^3-1}$ ? The numerator is strange...
Originally Posted by alex_nicole from n=1 to infinity of: (2n+n)/(5n^3 -1) Good luck!!! I hate these Are you sure it's $\displaystyle 2n+n$ in the numerator?
yea i know the numerator is crazy and should just be 3n right? but thats what it is.
Originally Posted by alex_nicole from n=1 to infinity of: (2n+n)/(5n^3 -1) Good luck!!! I hate these What I would do is show that $\displaystyle \frac{3n}{5n^3-1}$, term for term, is less than $\displaystyle \frac{1}{n^2}$. You know that $\displaystyle \sum\frac{1}{n^2}$ converges.
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