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Math Help - another series problem for my peeps

  1. #1
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    another series problem for my peeps

    from n=1 to infinity of:

    (2n+n)/(5n^3 -1)

    Good luck!!!

    I hate these
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  2. #2
    Super Member flyingsquirrel's Avatar
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    Is it \sum\frac{2n+n}{5n^3-1} ? The numerator is strange...
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  3. #3
    Member disclaimer's Avatar
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    Quote Originally Posted by alex_nicole View Post
    from n=1 to infinity of:

    (2n+n)/(5n^3 -1)

    Good luck!!!

    I hate these
    Are you sure it's 2n+n in the numerator?
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  4. #4
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    yea i know the numerator is crazy and should just be 3n right? but thats what it is.
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  5. #5
    MHF Contributor
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    Quote Originally Posted by alex_nicole View Post
    from n=1 to infinity of:

    (2n+n)/(5n^3 -1)

    Good luck!!!

    I hate these
    What I would do is show that \frac{3n}{5n^3-1}, term for term, is less than \frac{1}{n^2}. You know that \sum\frac{1}{n^2} converges.
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