another series problem for my peeps

**alex_nicole** · April 24th 2008, 08:53 AM

from n=1 to infinity of:

(2n+n)/(5n^3 -1)

Good luck!!!

I hate these

**flyingsquirrel** · April 24th 2008, 09:02 AM

Is it $\sum\frac{2n+n}{5n^3-1}$ ? The numerator is strange...

**disclaimer** · April 24th 2008, 09:03 AM

Originally Posted by alex_nicole

from n=1 to infinity of:

(2n+n)/(5n^3 -1)

Good luck!!!

I hate these

Are you sure it's $2n+n$ in the numerator?

**alex_nicole** · April 24th 2008, 09:06 AM

yea i know the numerator is crazy and should just be 3n right? but thats what it is.

**icemanfan** · April 24th 2008, 09:10 AM

Originally Posted by alex_nicole

from n=1 to infinity of:

(2n+n)/(5n^3 -1)

Good luck!!!

I hate these

What I would do is show that $\frac{3n}{5n^3-1}$ , term for term, is less than $\frac{1}{n^2}$ . You know that $\sum\frac{1}{n^2}$ converges.

Thread: another series problem for my peeps