# Thread: another series problem for my peeps

1. ## another series problem for my peeps

from n=1 to infinity of:

(2n+n)/(5n^3 -1)

Good luck!!!

I hate these

2. Is it $\sum\frac{2n+n}{5n^3-1}$ ? The numerator is strange...

3. Originally Posted by alex_nicole
from n=1 to infinity of:

(2n+n)/(5n^3 -1)

Good luck!!!

I hate these
Are you sure it's $2n+n$ in the numerator?

4. yea i know the numerator is crazy and should just be 3n right? but thats what it is.

5. Originally Posted by alex_nicole
from n=1 to infinity of:

(2n+n)/(5n^3 -1)

Good luck!!!

I hate these
What I would do is show that $\frac{3n}{5n^3-1}$, term for term, is less than $\frac{1}{n^2}$. You know that $\sum\frac{1}{n^2}$ converges.