# Math Help - Question-1

1. ## Question-1

Question says;

If A and B are positive numbers

How many different numbers can a be?

2. Hello,

$a^2-b^2=(a-b)(a+b)$

How many possibilities are there for a and b, being positive ?

3. Originally Posted by johnerdem
Question says;

If A and B are positive numbers

How many different numbers can a be?

You have $\frac{a^2-b^2}{a-b}=10,\ a,b \in \mathbb{Z}_+$

So (as $a \ne b$ ):

$a^2-b^2=10(a-b)\ \ \ \ \ ...(1)$

but $a^2-b^2=(a+b)(a-b)$ , so $(1)$ becomes:

$a+b=10\ \ \ \ \ ...(1)$

Now just enumerate the posibilities for $a$

RonL