How do I do this

A+3 over 8 + a over 5 = 2

how do i solve and check it?

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- Jun 21st 2006, 09:47 PMhappyboyhelp :)
How do I do this

A+3 over 8 + a over 5 = 2

how do i solve and check it? - Jun 21st 2006, 10:40 PMmalaygoelQuote:

Originally Posted by**happyboy**

Keep Smiling

Malay - Jun 22nd 2006, 12:40 AMnath_quam
A = 5 cross multiple the LHS so u get 5A + 15 + 8A all over 40 = 2 the rest is easy

- Jun 22nd 2006, 04:24 AMQuickQuote:

Originally Posted by**happyboy**

$\displaystyle \frac{A+3}{8}+\frac{a}{5}=2 $ you need a common denominator

$\displaystyle \frac{\left(A+3\right)\cdot5}{8\cdot5}+\frac{a \cdot 8}{5 \cdot 8}=2 $ Simplify

$\displaystyle \frac{5A+15}{40}+\frac{8a}{40}=2 $ add the fractions..

$\displaystyle \frac{5A+15+8a}{40}=2 $ Multiply both sides by 40

$\displaystyle 5A+15+8a=2\cdot40 $ subtract 15 from both sides

$\displaystyle 5A+8a=80-15 $ It's possible now to solve for both "A" and "a" but did you do a typo and they're really the same variable?

$\displaystyle 5A+8a=80-15 $ assuming they are...add them together

$\displaystyle 13A=65 $ and divide by 13

$\displaystyle A=65\div13 $ and the answer is....

$\displaystyle A=5 $ - Jun 22nd 2006, 08:40 AMThePerfectHackerQuote:

Originally Posted by**happyboy**

$\displaystyle \frac{\left( \frac{A+3}{8+A}\right)}{5}=2$

or,

$\displaystyle \frac{A+3}{\left( \frac{8+A}{5} \right)}=2$

Which one is it, if any?