# help :)

• Jun 21st 2006, 09:47 PM
happyboy
help :)
How do I do this
A+3 over 8 + a over 5 = 2
how do i solve and check it?
• Jun 21st 2006, 10:40 PM
malaygoel
Quote:

Originally Posted by happyboy
How do I do this
A+3 over 8 + a over 5 = 2
how do i solve and check it?

Take LCM and then cross multiply.

Keep Smiling
Malay
• Jun 22nd 2006, 12:40 AM
nath_quam
A = 5 cross multiple the LHS so u get 5A + 15 + 8A all over 40 = 2 the rest is easy
• Jun 22nd 2006, 04:24 AM
Quick
Quote:

Originally Posted by happyboy
How do I do this
A+3 over 8 + a over 5 = 2
how do i solve and check it?

It's easier to understand if you see the work...

$\displaystyle \frac{A+3}{8}+\frac{a}{5}=2$ you need a common denominator

$\displaystyle \frac{\left(A+3\right)\cdot5}{8\cdot5}+\frac{a \cdot 8}{5 \cdot 8}=2$ Simplify

$\displaystyle \frac{5A+15}{40}+\frac{8a}{40}=2$ add the fractions..

$\displaystyle \frac{5A+15+8a}{40}=2$ Multiply both sides by 40

$\displaystyle 5A+15+8a=2\cdot40$ subtract 15 from both sides

$\displaystyle 5A+8a=80-15$ It's possible now to solve for both "A" and "a" but did you do a typo and they're really the same variable?

$\displaystyle 5A+8a=80-15$ assuming they are...add them together

$\displaystyle 13A=65$ and divide by 13

$\displaystyle A=65\div13$ and the answer is....

$\displaystyle A=5$
• Jun 22nd 2006, 08:40 AM
ThePerfectHacker
Quote:

Originally Posted by happyboy
How do I do this
A+3 over 8 + a over 5 = 2
how do i solve and check it?

You can mean,
$\displaystyle \frac{\left( \frac{A+3}{8+A}\right)}{5}=2$
or,
$\displaystyle \frac{A+3}{\left( \frac{8+A}{5} \right)}=2$
Which one is it, if any?