5b^2 - 14b - 3 = 0
This is what I did
14 = 14^2 - 4 (5)(-3) / 2(5)
14= 196 + 60 / 10
14= 256 / 10
How do I get the answer?

12x^2 - 5x = 2
I subtracted 2 and got
12x^2 - 5x - 2 = 0
5= 5^2 - 4 (12)(-2) / 2(12)
5= 25 + 96 /24
How do I get the answer?
Thanks

2. Originally Posted by rowdy3
5b^2 - 14b - 3 = 0
This is what I did
14 = 14^2 - 4 (5)(-3) / 2(5)
14= 196 + 60 / 10
14= 256 / 10
How do I get the answer?

12x^2 - 5x = 2
I subtracted 2 and got
12x^2 - 5x - 2 = 0
5= 5^2 - 4 (12)(-2) / 2(12)
5= 25 + 96 /24
How do I get the answer?
Thanks
use the quadractic equation $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a,b,c and correspond to $ax^2+bx+c$

3. yeah, you need to set it equal to zero and then use the quadratic equation listed above.
you've got it right except remember to square it

so your set up for the first one will be:
$x = \frac{14 \pm \sqrt{(-14)^2 - 4(5)(-3)}}{2(5)}$