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Math Help - stuck on logs

  1. #1
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    stuck on logs

    log (p^-6/q^-2) =

    ??

    & log p^3/log q^7
    Last edited by bharriga; April 23rd 2008 at 10:15 AM. Reason: error
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  2. #2
    o_O
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    What are your expressions for x and y? You didn't provide them so we don't know what we're supposed to replace p and q with.

    Also:
    \frac{\log p^{3}}{\log q^{7}}\: {\color{red} \neq}\: \log \left(p^{3}q^{7}\right)^{\frac{1}{2}}

    Not sure how you made that step.
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  3. #3
    Moo
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    Quote Originally Posted by bharriga View Post
    log (p^-6/q^-2) =

    ??

    & log p^3/log q^7
    Hello,

    \log \frac ab = \log(a)-\log(b)

    \log a^b=b \log(a)

    So \log \frac{p^{-6}}{q^{-2}}=\log(p^{-6})-\log(q^{-2})=\dots
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  4. #4
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by Moo View Post
    Hello,

    \log \frac ab = \log(a)-\log(b)

    \log a^b=b \log(a)

    So \log \frac{p^{-6}}{q^{-2}}=\log(p^{-6})-\log(q^{-2})=\dots
    and working off of Moo's work we see that \log(p^{-6})-\log(q^{-2})=2\log(q)-6\log(p)

    \log(a^{c})=c\cdot\log(a)
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  5. #5
    Moo
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    I wanted bharriga think about it
    And I gave exactly the same formula as yours...
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  6. #6
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by Moo View Post
    I wanted bharriga think about it
    And I gave exactly the same formula as yours...
    Desole...c'etait le fois dehrnier
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