log (p^-6/q^-2) =
& log p^3/log q^7
Last edited by bharriga; April 23rd 2008 at 11:15 AM.
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What are your expressions for x and y? You didn't provide them so we don't know what we're supposed to replace p and q with.
Not sure how you made that step.
Originally Posted by bharriga log (p^-6/q^-2) =
& log p^3/log q^7 Hello,
Originally Posted by Moo Hello,
So and working off of Moo's work we see that
I wanted bharriga think about it
And I gave exactly the same formula as yours...
Originally Posted by Moo I wanted bharriga think about it
And I gave exactly the same formula as yours... Desole...c'etait le fois dehrnier
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