# Thread: stuck on logs

1. ## stuck on logs

log (p^-6/q^-2) =

??

& log p^3/log q^7

2. What are your expressions for x and y? You didn't provide them so we don't know what we're supposed to replace p and q with.

Also:
$\frac{\log p^{3}}{\log q^{7}}\: {\color{red} \neq}\: \log \left(p^{3}q^{7}\right)^{\frac{1}{2}}$

Not sure how you made that step.

3. Originally Posted by bharriga
log (p^-6/q^-2) =

??

& log p^3/log q^7
Hello,

$\log \frac ab = \log(a)-\log(b)$

$\log a^b=b \log(a)$

So $\log \frac{p^{-6}}{q^{-2}}=\log(p^{-6})-\log(q^{-2})=\dots$

4. Originally Posted by Moo
Hello,

$\log \frac ab = \log(a)-\log(b)$

$\log a^b=b \log(a)$

So $\log \frac{p^{-6}}{q^{-2}}=\log(p^{-6})-\log(q^{-2})=\dots$
and working off of Moo's work we see that $\log(p^{-6})-\log(q^{-2})=2\log(q)-6\log(p)$

$\log(a^{c})=c\cdot\log(a)$

5. I wanted bharriga think about it
And I gave exactly the same formula as yours...

6. Originally Posted by Moo
I wanted bharriga think about it
And I gave exactly the same formula as yours...
Desole...c'etait le fois dehrnier