I have this formula:

How do I convert this to a series with

From n = 1 to n = 10

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- June 21st 2006, 04:40 AMchanceySeries help
I have this formula:

How do I convert this to a series with

From n = 1 to n = 10 - June 21st 2006, 05:35 AMThePerfectHackerQuote:

Originally Posted by**chancey**

- June 21st 2006, 05:45 AMSoroban
Hello, Malay!

Edit: You're right! . . . *blush*

. . . . I'll correct it now.

Quote:

I have this formula:

How do I convert this to a series with

We have: .

We have a geometric series with first term and common ratio

The term is: .

Then: .

- June 21st 2006, 06:20 AMmalaygoelQuote:

Originally Posted by**Soroban**

It should be

Keep Smiling

Malay - June 21st 2006, 06:24 AMmalaygoelQuote:

Originally Posted by**chancey**

I observed that

Hence the given sequence is a G.P. with common ratio

Keep Smiling

Malay - June 21st 2006, 12:58 PMchancey
I need the series to do this:

Example (not the actual formula, changed it so the numbers were easier)

Where each number in the series has to be calculated with the previous number. My question is, can that be put into a series so that i can run a formula once to find or do I have to do it 10 times - June 21st 2006, 01:19 PMThePerfectHacker
As explained in the previous discussions this sequence is geometric, thus, if,

then,

or,

Where is the initial term.

Note, it is not possible to find , it can be anything number. - June 21st 2006, 01:27 PMSoroban
Hello, chancey!

Quote:

I need the series to do this:

Example (not the actual formula, changed it so the numbers were easier)

. Don't use decimals!

Where each number in the series has to be calculated with the previous number.

My question is, can that be put into a series so that i can run a formula once to find

or do I have to do it 10 times

. . and to be able to "eyeball" a sequence and determine its general form.

This sequence is: .

How long does it take for you to see that the denominators are*doubled*each time?

With a little thought, we see that the denominator is:

So the general term is: . - June 21st 2006, 10:30 PMchanceyQuote:

Originally Posted by**Soroban**

So: