Hello,Originally Posted bylalitchugh

I presume, that you know how to do a proof by induction.

A(1): n = 1. That means your equation becomes: 2 = 1*(1+1) which is true.

A(2): Let 2+4+6+...+2n = n(n+1) be true.

A(3): Proof that 2+4+6+...+2n+2(n+1)=n(n+1)+2(n+1). Factor the RHS

2+4+6+...+2n+2(n+1)=(n+1)(n+2)

2+4+6+...+2n+2(n+1)=(n+1)(n+1+1)

That means you've changed successfully the n's at the RHS into (n+1)'s. So this equation is true for all

Greetings

EB