3-1/x
3x-1
x^2
Hello, armygirltiff!
Multiply top and bottom by the LCD, $\displaystyle x^2$$\displaystyle \frac{3-\dfrac{1}{x}}{\dfrac{3x-1}{x^2}} $
. . $\displaystyle \frac{x^2\left(3 - \dfrac{1}{x}\right)}{x^2\left(\dfrac{3x-1}{x^2}\right)} \;=\;\frac{3x^2 - x}{3x-1} \;=\;\frac{x(3x-1)}{3x-1} \;=\;x$