Simplify the complex fraction

• Apr 21st 2008, 06:43 PM
armygirltiff
Simplify the complex fraction
3-1/x
3x-1
x^2
• Apr 21st 2008, 07:17 PM
Jhevon
Quote:

Originally Posted by armygirltiff
3-1/x
3x-1
x^2

you have to go through all your posts and clarify your fractions. we cannot understand what you are saying. i responded to one of your threads telling you how to fix this
• Apr 25th 2008, 08:18 AM
nikk
Quote:

Originally Posted by armygirltiff
3-1/x
3x-1
x^2

may be u can reupload it back after scane
• Apr 25th 2008, 08:31 AM
most likely it is (3-1/x) / [(3x-1) / (x^2)]

well if it is then:
(3-1/x) / [(3x-1) / (x^2)]
= (3-1/x)(x^2) / (3x-1)
= x(3x-1) / (3x-1)
= x
• Apr 25th 2008, 09:01 AM
Isomorphism
Quote:

Originally Posted by armygirltiff
3-1/x
3x-1
x^2

Let me guess:

$\frac{3 - {\frac1{x}}}{\frac{3x-1}{x^2}} = \frac{\frac{3x-1}{x}}{\frac{3x-1}{x^2}} =\frac{\frac1{x}}{\frac1{x^2}} = x$

This is what I would call, a nested \frac practice :p
• Apr 25th 2008, 10:39 AM
Soroban
Hello, armygirltiff!

Quote:

$\frac{3-\dfrac{1}{x}}{\dfrac{3x-1}{x^2}}$
Multiply top and bottom by the LCD, $x^2$

. . $\frac{x^2\left(3 - \dfrac{1}{x}\right)}{x^2\left(\dfrac{3x-1}{x^2}\right)} \;=\;\frac{3x^2 - x}{3x-1} \;=\;\frac{x(3x-1)}{3x-1} \;=\;x$