3-1/x

3x-1

x^2

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- Apr 21st 2008, 06:43 PMarmygirltiffSimplify the complex fraction
__3-1/x__

__3x-1__

x^2 - Apr 21st 2008, 07:17 PMJhevon
- Apr 25th 2008, 08:18 AMnikk
- Apr 25th 2008, 08:31 AMDanshader
most likely it is (3-1/x) / [(3x-1) / (x^2)]

well if it is then:

(3-1/x) / [(3x-1) / (x^2)]

= (3-1/x)(x^2) / (3x-1)

= x(3x-1) / (3x-1)

= x - Apr 25th 2008, 09:01 AMIsomorphism
- Apr 25th 2008, 10:39 AMSoroban
Hello, armygirltiff!

Quote:

$\displaystyle \frac{3-\dfrac{1}{x}}{\dfrac{3x-1}{x^2}} $

. . $\displaystyle \frac{x^2\left(3 - \dfrac{1}{x}\right)}{x^2\left(\dfrac{3x-1}{x^2}\right)} \;=\;\frac{3x^2 - x}{3x-1} \;=\;\frac{x(3x-1)}{3x-1} \;=\;x$