1. ## exponential equations

log(3x+5)= 3

13^(-x/9) = 17

i need help finding the solutions the negative threw me off.

2. The links to your pictures were flagged and rejected by my server.

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3. Originally Posted by pj Cala
log(3x+5)= 3

13^(-x/9) = 17

i need help finding the solutions the negative threw me off.
$log(3x+5)=3\Rightarrow{3x+5=10^3}\Rightarrow{x=\fr ac{10^3-5}{3}}$

$13^{\frac{-x}{9}}=17$...then by using our logarithim rules

$\frac{-x}{9}=log_{3}(17)\Rightarrow{x=-9log_{13}(17)}$