log(3x+5)= 3 13^(-x/9) = 17 i need help finding the solutions the negative threw me off.
Last edited by pj Cala; Apr 21st 2008 at 01:54 PM. Reason: its fixed as of now
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Originally Posted by pj Cala log(3x+5)= 3 13^(-x/9) = 17 i need help finding the solutions the negative threw me off. $\displaystyle log(3x+5)=3\Rightarrow{3x+5=10^3}\Rightarrow{x=\fr ac{10^3-5}{3}}$ $\displaystyle 13^{\frac{-x}{9}}=17$...then by using our logarithim rules $\displaystyle \frac{-x}{9}=log_{3}(17)\Rightarrow{x=-9log_{13}(17)}$
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