# exponential equations

• Apr 21st 2008, 01:32 PM
pj Cala
exponential equations
log(3x+5)= 3

13^(-x/9) = 17

i need help finding the solutions the negative threw me off.
• Apr 21st 2008, 01:44 PM
TKHunny
The links to your pictures were flagged and rejected by my server.

You may have to figure out a different way to communicate.
• Apr 21st 2008, 01:56 PM
Mathstud28
Quote:

Originally Posted by pj Cala
log(3x+5)= 3

13^(-x/9) = 17

i need help finding the solutions the negative threw me off.

$log(3x+5)=3\Rightarrow{3x+5=10^3}\Rightarrow{x=\fr ac{10^3-5}{3}}$

$13^{\frac{-x}{9}}=17$...then by using our logarithim rules

$\frac{-x}{9}=log_{3}(17)\Rightarrow{x=-9log_{13}(17)}$