X=1/1001 + 1/1002 + ........ + 1/3001 then.. a) X<1 b) X>3/2 c) 1<X<3/2 d) None of the above
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Originally Posted by biplab X=1/1001 + 1/1002 + ........ + 1/3001 then.. a) X<1 b) X>3/2 c) 1<X<3/2 d) None of the above c)
Thanks..but can anybody please hep me in detail solution...
Originally Posted by biplab X=1/1001 + 1/1002 + ........ + 1/3001 then.. a) X<1 b) X>3/2 c) 1<X<3/2 d) None of the above . I can give you an error estimate but you probably are not interested in that. Thus, . But . This means, .
Hello, Originally Posted by ThePerfectHacker I'm only curious : how do you get this approximation ? ?
Originally Posted by Moo I'm only curious : how do you get this approximation Since you ask I would have to give you the error term as well. Consider the function on the interval where is an integer. Then, approximating by Riemann sums, Thus, . This is Mine 94th Post!!!
Oh I see, I was looking towards power series and Taylor series ^^' Thanks
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