# Math Help - dividing cubed roots

1. ## dividing cubed roots

$\sqrt[3]{270}/\sqrt[3]{10}$

2. i was not sure how to make the cubed root of 270 go on to of the cubed root of 10 but thats the problem

3. $\frac{\sqrt[3]{270}}{\sqrt[3]{10}} = \sqrt[3]{\frac{270}{10}} = \text{etc.}$

This works since:
$\frac{a^{c}}{b^{c}} = \left(\frac{a}{b}\right)^{c}$

where in this case $c = \frac{1}{3}$

4. so its basically 270/10=27 then the cubed rot of 27 is 3 is that the answer or am i going in the wrrgone direction?

5. Hello,

This is correct