$\displaystyle \sqrt[3]{270}/\sqrt[3]{10}$
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i was not sure how to make the cubed root of 270 go on to of the cubed root of 10 but thats the problem
$\displaystyle \frac{\sqrt[3]{270}}{\sqrt[3]{10}} = \sqrt[3]{\frac{270}{10}} = \text{etc.}$ This works since: $\displaystyle \frac{a^{c}}{b^{c}} = \left(\frac{a}{b}\right)^{c}$ where in this case $\displaystyle c = \frac{1}{3}$
so its basically 270/10=27 then the cubed rot of 27 is 3 is that the answer or am i going in the wrrgone direction?
Hello, This is correct
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