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Math Help - dividing square roots

  1. #1
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    dividing square roots

    \sqrt{35x}/\sqrt{7x}
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  2. #2
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    was not sure how to write it but the the square root of 35x on top and the square root of 7x on the bottem
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  3. #3
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by imbadatmath View Post
    \sqrt{35x}/\sqrt{7x}
    how about I give you a BIG hint...this can be rewritten as \bigg(\frac{35x}{7x}\bigg)^{\frac{1}{2}}
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    im still confused lol
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  5. #5
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    y would i make it into a multuplication problem?
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  6. #6
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    It's not a multiplication problem ... Basically, MathStud put the two square roots into one:

    \frac{\sqrt{35x}}{\sqrt{7x}} = \sqrt{\frac{35x}{7x}} = \text{Etc.}

    since as he said:
    \frac{a^{c}}{b^{c}} = \left(\frac{a}{b}\right)^{c}

    where c = \frac{1}{2} here
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  7. #7
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    so its basically 35/7 equals 5? is that the answer?
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    Forum Admin topsquark's Avatar
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    Quote Originally Posted by imbadatmath View Post
    so its basically 35/7 equals 5? is that the answer?
    \sqrt{\frac{35}{7}} = \sqrt{5}
    If that's what you meant, then yes.

    -Dan
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