# Thread: dividing square roots

1. ## dividing square roots

$\sqrt{35x}/\sqrt{7x}$

2. was not sure how to write it but the the square root of 35x on top and the square root of 7x on the bottem

3. Originally Posted by imbadatmath
$\sqrt{35x}/\sqrt{7x}$
how about I give you a BIG hint...this can be rewritten as $\bigg(\frac{35x}{7x}\bigg)^{\frac{1}{2}}$

4. im still confused lol

5. y would i make it into a multuplication problem?

6. It's not a multiplication problem ... Basically, MathStud put the two square roots into one:

$\frac{\sqrt{35x}}{\sqrt{7x}} = \sqrt{\frac{35x}{7x}} = \text{Etc.}$

since as he said:
$\frac{a^{c}}{b^{c}} = \left(\frac{a}{b}\right)^{c}$

where $c = \frac{1}{2}$ here

7. so its basically 35/7 equals 5? is that the answer?

8. Originally Posted by imbadatmath
so its basically 35/7 equals 5? is that the answer?
$\sqrt{\frac{35}{7}} = \sqrt{5}$
If that's what you meant, then yes.

-Dan