Math Help - sqaure roots

1. sqaure roots

$\sqrt{y+4}-2 = 3$

2. Originally Posted by imbadatmath
$\sqrt{y+4}-2 = 3$
add two to both sides, so you get

$\sqrt{y + 4} = 5$

now square both sides and continue. Check the solution when done, squaring often introduces erroneous solutions

Originally Posted by imbadatmath
any help would be greatly appreciated
stop making posts like these. it is seen as begging and bumping, which is against the rules.

3. im sorry wont happen agian but what do i do after this step?

4. if i square both sides i get y+4=25 then i subtrace 4 from both sides and i get y=21 is this correct?

5. well 21 plus 4 is 25 then the square root of 25 is 5 so 5 -2=3 so 21 is the correct answer?

6. Originally Posted by imbadatmath
well 21 plus 4 is 25 then the square root of 25 is 5 so 5 -2=3 so 21 is the correct answer?
If your solution works in the original equation, it's the answer.

Yes, you have got it.

-Dan