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Math Help - sqaure roots

  1. #1
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    sqaure roots

    \sqrt{y+4}-2 = 3
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by imbadatmath View Post
    \sqrt{y+4}-2 = 3
    add two to both sides, so you get

    \sqrt{y + 4} = 5

    now square both sides and continue. Check the solution when done, squaring often introduces erroneous solutions

    Quote Originally Posted by imbadatmath View Post
    any help would be greatly appreciated
    stop making posts like these. it is seen as begging and bumping, which is against the rules.
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    im sorry wont happen agian but what do i do after this step?
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  4. #4
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    if i square both sides i get y+4=25 then i subtrace 4 from both sides and i get y=21 is this correct?
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    well 21 plus 4 is 25 then the square root of 25 is 5 so 5 -2=3 so 21 is the correct answer?
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  6. #6
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by imbadatmath View Post
    well 21 plus 4 is 25 then the square root of 25 is 5 so 5 -2=3 so 21 is the correct answer?
    If your solution works in the original equation, it's the answer.

    Yes, you have got it.

    -Dan
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