1. ## sqaure roots

$\sqrt{y+4}-2 = 3$

$\sqrt{y+4}-2 = 3$
add two to both sides, so you get

$\sqrt{y + 4} = 5$

now square both sides and continue. Check the solution when done, squaring often introduces erroneous solutions

any help would be greatly appreciated
stop making posts like these. it is seen as begging and bumping, which is against the rules.

3. im sorry wont happen agian but what do i do after this step?

4. if i square both sides i get y+4=25 then i subtrace 4 from both sides and i get y=21 is this correct?

5. well 21 plus 4 is 25 then the square root of 25 is 5 so 5 -2=3 so 21 is the correct answer?