# sqaure roots

• Apr 20th 2008, 03:32 PM
sqaure roots
$\sqrt{y+4}-2 = 3$
• Apr 20th 2008, 03:43 PM
Jhevon
Quote:

$\sqrt{y+4}-2 = 3$

add two to both sides, so you get

$\sqrt{y + 4} = 5$

now square both sides and continue. Check the solution when done, squaring often introduces erroneous solutions

Quote:

any help would be greatly appreciated

stop making posts like these. it is seen as begging and bumping, which is against the rules.
• Apr 20th 2008, 03:44 PM
im sorry wont happen agian but what do i do after this step?
• Apr 20th 2008, 03:59 PM
if i square both sides i get y+4=25 then i subtrace 4 from both sides and i get y=21 is this correct?
• Apr 20th 2008, 04:05 PM