# sqaure roots

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• Apr 20th 2008, 03:32 PM
imbadatmath
sqaure roots
$\sqrt{y+4}-2 = 3$
• Apr 20th 2008, 03:43 PM
Jhevon
Quote:

Originally Posted by imbadatmath
$\sqrt{y+4}-2 = 3$

add two to both sides, so you get

$\sqrt{y + 4} = 5$

now square both sides and continue. Check the solution when done, squaring often introduces erroneous solutions

Quote:

Originally Posted by imbadatmath
any help would be greatly appreciated

stop making posts like these. it is seen as begging and bumping, which is against the rules.
• Apr 20th 2008, 03:44 PM
imbadatmath
im sorry wont happen agian but what do i do after this step?
• Apr 20th 2008, 03:59 PM
imbadatmath
if i square both sides i get y+4=25 then i subtrace 4 from both sides and i get y=21 is this correct?
• Apr 20th 2008, 04:05 PM
imbadatmath
well 21 plus 4 is 25 then the square root of 25 is 5 so 5 -2=3 so 21 is the correct answer?
• Apr 20th 2008, 06:49 PM
topsquark
Quote:

Originally Posted by imbadatmath
well 21 plus 4 is 25 then the square root of 25 is 5 so 5 -2=3 so 21 is the correct answer?

If your solution works in the original equation, it's the answer. :)

Yes, you have got it.

-Dan