who know how to convert z/(z^2+9) to z/(z+3i)/(z-3i)?i really do not have any idea how the book convert it.
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What else ?
no,look carefully at the question,i want to ask why z^2+9=(z+3i)/(z-3i)
This is not possible
Perhaps they meant which is
thanks,i think you are right.by the way,in another question,i saw it write 1/(z^2+1)=(1/2i)/(z-i) - (1/2i)/(z+i).how they did it?
Woah, it's better when you put the parenthesis where it has to go
The numerator has to be equal to 1.
So develop, then group the terms including z and write that its coefficient must be null since z doesn't appear in "1".
Solve for a, b, c and d
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