1. ## Rationalize the denominator

Can anyone help me figure this problem out step by step? All help would be appreciated.

3/6-√2

Can anyone help me figure this problem out step by step? All help would be appreciated.

3/6-√2

use the conjugate

so we have $6-\sqrt{2}$ its conjugate is $6+\sqrt{2}$

mult the numerator and denominator by the conjugate to get

$\frac{3}{6-\sqrt{2}} \cdot \frac{6+\sqrt{2}}{6+\sqrt{2}}=\frac{18+3\sqrt{2}}{ 6-2}=\frac{9}{2}+\frac{3}{4}\sqrt{2}$

3. ## Rationalize the denominator

OMG Thanks.

But can you explain after you multiply by conjugate how did you get the negative for the radical.