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Math Help - Rationalize the denominator

  1. #1
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    Unhappy Rationalize the denominator

    Can anyone help me figure this problem out step by step? All help would be appreciated.


    3/6-√2


    √=radical
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by typaradise View Post
    Can anyone help me figure this problem out step by step? All help would be appreciated.


    3/6-√2


    √=radical
    use the conjugate

    so we have 6-\sqrt{2} its conjugate is 6+\sqrt{2}

    mult the numerator and denominator by the conjugate to get

    \frac{3}{6-\sqrt{2}} \cdot \frac{6+\sqrt{2}}{6+\sqrt{2}}=\frac{18+3\sqrt{2}}{  6-2}=\frac{9}{2}+\frac{3}{4}\sqrt{2}
    Last edited by TheEmptySet; April 19th 2008 at 06:02 PM. Reason: typo
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  3. #3
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    Rationalize the denominator

    OMG Thanks.

    But can you explain after you multiply by conjugate how did you get the negative for the radical.
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  4. #4
    Behold, the power of SARDINES!
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    Quote Originally Posted by typaradise View Post
    OMG Thanks.

    But can you explain after you multiply by conjugate how did you get the negative for the radical.
    It shouldn't have been negative. I fixed my post above.

    Good luck.
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