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Thread: Factoring Completely...

  1. April 18th 2008, 08:52 PM #1
    eraser851
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    Factoring Completely...

    Alright, I've got one more question. Could someone explain how to factor this completely?

    16z^4-x^4z^4
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  2. April 18th 2008, 09:52 PM #2
    Aryth
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    Well, we have:

    16z^4 - x^4z^4

    1. Factor out a z^4

    z^4(16 - x^4)

    2. Factor the difference of squares:

    z^4(4 + x^2)(4 - x^2)

    3. Factor the other difference of squares:

    z^4(4 + x^2)((2 + x)(2 - x))

    And there you go.
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  3. April 18th 2008, 09:53 PM #3
    eraser851
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    Ah, thank you so much!
    That helps!
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