Alright, I've got one more question. Could someone explain how to factor this completely?

$\displaystyle 16z^4-x^4z^4$

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- Apr 18th 2008, 08:52 PMeraser851Factoring Completely...
Alright, I've got one more question. Could someone explain how to factor this completely?

$\displaystyle 16z^4-x^4z^4$ - Apr 18th 2008, 09:52 PMAryth
Well, we have:

$\displaystyle 16z^4 - x^4z^4$

1. Factor out a $\displaystyle z^4$

$\displaystyle z^4(16 - x^4)$

2. Factor the difference of squares:

$\displaystyle z^4(4 + x^2)(4 - x^2)$

3. Factor the other difference of squares:

$\displaystyle z^4(4 + x^2)((2 + x)(2 - x))$

And there you go. - Apr 18th 2008, 09:53 PMeraser851
Ah, thank you so much!

That helps!