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Math Help - 2 problems

  1. #1
    Newbie
    Joined
    Mar 2008
    Posts
    14

    2 problems

    Hello everyone. I've got two problems that I'm trying to solve, but I just can't seem to get it. Could someone explain the solutions to me?

    Here's the first one:
    Solve where t is a real number. Simplify your answer as much as possible.
    If there is more than one solution, separate them with commas.
    (t+1)^2-48=0

    And the second:
    Solve the following equation for x by using the quadratic formula:
    <br />
2x^2-4x-4=0<br />
    If there is more than one solution, separate them with commas.

    Thanks so much, guys!
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  2. #2
    MHF Contributor Mathstud28's Avatar
    Joined
    Mar 2008
    From
    Pennsylvania
    Posts
    3,641
    Quote Originally Posted by tony_rose88 View Post
    Hello everyone. I've got two problems that I'm trying to solve, but I just can't seem to get it. Could someone explain the solutions to me?

    Here's the first one:
    Solve where t is a real number. Simplify your answer as much as possible.
    If there is more than one solution, separate them with commas.
    (t+1)^2-48=0

    And the second:
    Solve the following equation for x by using the quadratic formula:
    <br />
2x^2-4x-4=0<br />
    If there is more than one solution, separate them with commas.

    Thanks so much, guys!
    (t+1)^2=48\Rightarrow{|t+1|=\sqrt{48}}\Rightarrow{  t=-\sqrt{48}-1,t=\sqrt{48}-1}
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