Hi,
For my FST project, I am supposed to factor n^3 - 8 = 0
So,
I turn it into the difference of cubes:
(n)^3 - (2)^3
Which ends up being:
(n - 2) (n^2 + 2n + 4)
So, (n-2) is one factor. However, I don't know how to find the other zeros. I need to factor (n^2 + 2n + 4), but I can't seem to figure it out.
Thanks!
Ethan
Alright, let me try this:
(n^2 + 2n + 4) =
-2 +/- root{2^2 - 4(1)(4)
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2
This equals:
-2 +/- root{-12
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2
This equals:
-2 +/- i root{12
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2
This equals:
-2 +/1 2i root {3
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2
Question: Now is it okay to divide everything by 2?
-1 +/- i root{3
So, would those be my factors? (-1+ i root{3)(-1 - i root{3)
I have a strong feeling I went wrong somewhere along the line...
(By the way, I apologize for having to write out "+/-" and "root{". How do you draw out the math problem like so many on this forum do?)
Thanks,
Ethan