Hi,

For my FST project, I am supposed to factor n^3 - 8 = 0

So,

I turn it into the difference of cubes:

(n)^3 - (2)^3

Which ends up being:

(n - 2) (n^2 + 2n + 4)

So, (n-2) is one factor. However, I don't know how to find the other zeros. I need to factor (n^2 + 2n + 4), but I can't seem to figure it out.

Thanks!

Ethan