1. ## help me again please

B raise to m times B raise to m...

2. Originally Posted by uzagie
B raise to m times B raise to m...
$B^m\cdot B^m=B^{(m+m)}$

Chech with numbers.

$3^2\cdot3^2=3^{(2+2)}=3^4=81$

rules of powers:

$a^b\cdot a^c=a^{(b+c)}$
$\left(a^b\right)^c=a^{(b\cdot c)}$
$a^b+ a^b=2a^b$
$\left(a\cdot b\right)^c=a^c\cdot b^c$
and
$\left(a+b\right)^c$ can't be easily simplified

3. Hi:

Of course you know that m+m=2m, and therefore b^(m+m) simplifies to b^(2m). Not a big deal but, perhaps enough save you a couple of points on the test/exam.

By the way, why is this question posted in two different locations within this site? As a result, three people have invested valuable time doing the job of one.

With regard to your posts, you may wish to recheck them for accuracy. They are not the same question, although I suspect they were intended to be.

Finally, the use of ellipses (...) when communicating mathematics should be approached with care. They carry specific meaning within the math world, and can therefore be misinturpreted by the reader. For instance, in the present case,

"b raised to m times b raised to m..." would indicate the expression goes on ad infinitum, giving

(b^m)(b^m)(b^m)(b^m)...= b^(m+m+m+...) = lim(b^(km))_[k->inf].

...so there you have it.

Regards,

Rich B.