mod[(z-z1)/(z-z2)] = k where k is not equal to 1 represents a circle. how?
Hello, Navesh!
also simplifying the eqn. we get
. . . not quite
which makes the constt. term +ve, hence makes the circle real. Am I OK?
We have: .
Expand: .
Rearrange: .
Factor: .
Hence: .
. . .Or: .
And we see the restrictions on the constants.
Obviously:
But equally important, the right side must be positive.
Hence: . and
. . . or: . and