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Math Help - Word problem.. anyone?

  1. #1
    Junior Member
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    Apr 2008
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    Word problem.. anyone?

    Liquid A has 10 grams of element X per liter. Liquid B has 15 milligrams of element Y per cm^3 (there are 1000 milligrams in a gram and 1000 cm^3 in a liter). It is desired to make 130 grams of molecule Z. To make 18 grams of Z requires 2 grams of X and 16 grams of Y. How many liters of each liquid should be used?
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  2. #2
    Member
    Joined
    Aug 2007
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    I will quickly try to tackle this.

    We have;

    (1)~~~A~=~10gl^{-1}~of~X

    (2)~~~B~=~15mgcm^{-3}~of~Y

    ~=~15\cdot10^{-3}gcm^{-3}

    ~=~15gl^{-1}

    18g~of~Z~=~2g~of~X~+~16g~of~Y

    \implies~130g~of~Z~=~\frac{130}{9}g~of~X~+~\frac{1  040}{9}g~of~Y

    We want \frac{130}{9}g~of~X hence we need \frac{130}{90}l of A
    We also want \frac{1040}{9}g~of~Y hence need \frac{208}{27}l of B
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