been stuck on this for ages...
x²+4y²=10
2y+3x=10
cant get the answer... can any1 do it please... its my gcse pratice paper
Looking at the first question, note the blue:
$\displaystyle x^{2} + 4y^{2} = 10$
$\displaystyle x^{2} + {\color{blue} (2y)^{2}} = 10$
From your second equation:
$\displaystyle {\color{blue}2y} + 3x = 10$
$\displaystyle {\color{blue}2y} = 10 - 3x$
So plug 2y from the second equation to your first one:
$\displaystyle x^{2} + \left(10 - 3x\right)^{2} = 10$
Expand, move everything to one side, and solve the quadratic