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Math Help - Any chance of some help? please:(

  1. #1
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    Any chance of some help? please:(

    been stuck on this for ages...

    x+4y=10
    2y+3x=10

    cant get the answer... can any1 do it please... its my gcse pratice paper
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  2. #2
    o_O
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    Looking at the first question, note the blue:
    x^{2} + 4y^{2} = 10
    x^{2} + {\color{blue} (2y)^{2}} = 10

    From your second equation:
    {\color{blue}2y} + 3x = 10
    {\color{blue}2y} = 10 - 3x

    So plug 2y from the second equation to your first one:
    x^{2} + \left(10 - 3x\right)^{2} = 10

    Expand, move everything to one side, and solve the quadratic
    Last edited by o_O; April 16th 2008 at 12:58 PM.
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  3. #3
    Moo
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    Hello o_O...

    Unfortunately, it's x+4y, not x-4y

    If we continue it, we finally get :

    x^{2} {\color{red} +} \left(10 - 3x\right)^{2} = 10
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  4. #4
    o_O
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    Merci, mon amie franaise
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  5. #5
    Moo
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    You're welcome dear
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