# Math Help - Any chance of some help? please:(

1. ## Any chance of some help? please:(

been stuck on this for ages...

x²+4y²=10
2y+3x=10

cant get the answer... can any1 do it please... its my gcse pratice paper

2. Looking at the first question, note the blue:
$x^{2} + 4y^{2} = 10$
$x^{2} + {\color{blue} (2y)^{2}} = 10$

${\color{blue}2y} + 3x = 10$
${\color{blue}2y} = 10 - 3x$

So plug 2y from the second equation to your first one:
$x^{2} + \left(10 - 3x\right)^{2} = 10$

Expand, move everything to one side, and solve the quadratic

3. Hello o_O...

Unfortunately, it's x²+4y², not x²-4y²

If we continue it, we finally get :

$x^{2} {\color{red} +} \left(10 - 3x\right)^{2} = 10$

4. Merci, mon amie française

5. You're welcome dear