# Math Help - logarithms

1. ## logarithms

Hey , im doing logarithms, and im stuck with this question, could you please explain to me how to do it...thank you

2. Originally Posted by Chez_
Hey , im doing logarithms, and im stuck with this question, could you please explain to me how to do it...thank you
Hello Chez!

Where is the question?

3. Lol how daft am i lol

I want to know how to go about these types of Q's

express the following in terms of x
log square root x
longx^3/2+log3squareroot 3 , iv done others of those but not sure on those.
2logbase 10x-long base107 need to express that as a single logarithm.

as logarithms with base 10 how do i solve these types of q..1.08^x=2 and 0.99^x=0.000001 eg..
Thank you x

4. Originally Posted by Chez_
Lol how daft am i lol

I want to know how to go about these types of Q's

express the following in terms of x
i)log square root x

ii)longx^3/2+log3squareroot 3 , iv done others of those but not sure on those.

iii)2logbase 10x-long base107 need to express that as a single logarithm.

iv) as logarithms with base 10 how do i solve these types of q..1.08^x=2 and 0.99^x=0.000001 eg..
Thank you x

i) $\log \sqrt{x} = \frac{1}{2} \log x$ (Is this what you mean?)

ii) $\frac{3}{2} \log {x} + \frac{1}{2} \log_{3} {3} = \frac{3}{2} \log {x} + \frac{1}{2}$

iii) $2 \log _{10} x - \log_{10} {7} = \log _{10} x^2 - \log_{10} {7} = \log _{10} \frac{x^2}{7}$

$iv) 1.08^x = 2 \rightarrow x = \log _{1.08} 2$

5. Use the following properties:
$\log_a\left(A\cdot B\right)=\log_aA+\log_aB$
$\displaystyle\log_a\frac{A}{B}=\log_aA-\log_aB$
$\log_aA^{\alpha}=\alpha\log_aA$