Hey , im doing logarithms, and im stuck with this question, could you please explain to me how to do it...thank you
Lol how daft am i lol
I want to know how to go about these types of Q's
express the following in terms of x
log square root x
longx^3/2+log3squareroot 3 , iv done others of those but not sure on those.
2logbase 10x-long base107 need to express that as a single logarithm.
as logarithms with base 10 how do i solve these types of q..1.08^x=2 and 0.99^x=0.000001 eg..
Thank you x
i) $\displaystyle \log \sqrt{x} = \frac{1}{2} \log x $ (Is this what you mean?)
ii) $\displaystyle \frac{3}{2} \log {x} + \frac{1}{2} \log_{3} {3} = \frac{3}{2} \log {x} + \frac{1}{2}$
iii) $\displaystyle 2 \log _{10} x - \log_{10} {7} = \log _{10} x^2 - \log_{10} {7} = \log _{10} \frac{x^2}{7}$
$\displaystyle iv) 1.08^x = 2 \rightarrow x = \log _{1.08} 2$