Results 1 to 5 of 5

Math Help - logarithms

  1. #1
    Member
    Joined
    Dec 2007
    Posts
    80

    Exclamation logarithms

    Hey , im doing logarithms, and im stuck with this question, could you please explain to me how to do it...thank you
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Bar0n janvdl's Avatar
    Joined
    Apr 2007
    From
    Meh
    Posts
    1,630
    Thanks
    6
    Quote Originally Posted by Chez_ View Post
    Hey , im doing logarithms, and im stuck with this question, could you please explain to me how to do it...thank you
    Hello Chez!

    Where is the question?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Dec 2007
    Posts
    80
    Lol how daft am i lol

    I want to know how to go about these types of Q's

    express the following in terms of x
    log square root x
    longx^3/2+log3squareroot 3 , iv done others of those but not sure on those.
    2logbase 10x-long base107 need to express that as a single logarithm.

    as logarithms with base 10 how do i solve these types of q..1.08^x=2 and 0.99^x=0.000001 eg..
    Thank you x
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Bar0n janvdl's Avatar
    Joined
    Apr 2007
    From
    Meh
    Posts
    1,630
    Thanks
    6
    Quote Originally Posted by Chez_ View Post
    Lol how daft am i lol

    I want to know how to go about these types of Q's

    express the following in terms of x
    i)log square root x

    ii)longx^3/2+log3squareroot 3 , iv done others of those but not sure on those.

    iii)2logbase 10x-long base107 need to express that as a single logarithm.

    iv) as logarithms with base 10 how do i solve these types of q..1.08^x=2 and 0.99^x=0.000001 eg..
    Thank you x

    i) \log \sqrt{x} = \frac{1}{2} \log x (Is this what you mean?)

    ii) \frac{3}{2} \log {x} + \frac{1}{2} \log_{3} {3} = \frac{3}{2} \log {x} + \frac{1}{2}

    iii) 2 \log _{10} x - \log_{10} {7} =  \log _{10} x^2 - \log_{10} {7} = \log _{10} \frac{x^2}{7}

    iv) 1.08^x = 2 \rightarrow x = \log _{1.08} 2
    Follow Math Help Forum on Facebook and Google+

  5. #5
    MHF Contributor red_dog's Avatar
    Joined
    Jun 2007
    From
    Medgidia, Romania
    Posts
    1,252
    Thanks
    5
    Use the following properties:
    \log_a\left(A\cdot B\right)=\log_aA+\log_aB
    \displaystyle\log_a\frac{A}{B}=\log_aA-\log_aB
    \log_aA^{\alpha}=\alpha\log_aA
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. logarithms help
    Posted in the Algebra Forum
    Replies: 4
    Last Post: April 6th 2010, 06:29 PM
  2. Logarithms
    Posted in the Algebra Forum
    Replies: 2
    Last Post: April 6th 2010, 04:46 PM
  3. logarithms
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: March 24th 2010, 04:26 AM
  4. Logarithms
    Posted in the Algebra Forum
    Replies: 3
    Last Post: March 18th 2010, 02:52 PM
  5. Logarithms help
    Posted in the Algebra Forum
    Replies: 2
    Last Post: March 16th 2010, 04:30 AM

Search Tags


/mathhelpforum @mathhelpforum