hello!!! x+3λy=1 λx-3λy=2λ+1 and 3x+αy=3 αx+3y=3 please help me.
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Originally Posted by gdespina hello!!! x+3λy=1 λx-3λy=2λ+1 and 3x+αy=3 αx+3y=3 please help me. x+3λy=1 λx-3λy=2λ+1 Add these two equations together to get: $\displaystyle x+x\lambda + 3y\lambda - 3y\lambda = 1 + 2\lambda + 1$ $\displaystyle x(1+\lambda) = 2(1+\lambda)$ $\displaystyle x=2$ Plug back into either of the equations to solve for y.
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