absolute values and quad. formulae
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How about you solve for x from the original quadratic? Therefore, and , since we let You can now solve for m.
Last edited by colby2152; April 16th 2008 at 06:55 AM.
Originally Posted by colby2152 since So, as ?
Originally Posted by flyingsquirrel So, as ? Okay, we let
Originally Posted by colby2152 How about you solve for x from the original quadratic? Therefore, and , since we let You can now solve for m. i still don't understand. Why shouldn't squaring the both sides is the only way to do it? thanks for help!
Originally Posted by afeasfaerw23231233 i still don't understand. Why shouldn't squaring the both sides is the only way to do it? thanks for help! No, keep the absolute value sign on the right side because there could be a negative.
Originally Posted by afeasfaerw23231233 i still don't understand. Why shouldn't squaring the both sides is the only way to do it? thanks for help! Denoting it by Consider two cases x > y and x <= y and then reduce it to and respectively. Now consider each case separately, and solve for m and check if the assumed condition (x > y or x <= y) satisfies.
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