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Thread: Expanding and simplifying

  1. April 15th 2008, 05:27 PM #1
    Maths409
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    Expanding and simplifying

    can anyone help me expand and simplify this please:




    thanks
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  2. April 15th 2008, 05:31 PM #2
    Mathstud28
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    Quote Originally Posted by Maths409 View Post
    can anyone help me expand and simplify this please:




    thanks
    I assume you mean expand and combine like factors well...I will expand it for you and you show us the work to combine the factors x^2+3x^2+8\sqrt{3}x+16-[3x^2+8\sqrt{3}x+16]=0
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  3. April 15th 2008, 05:37 PM #3
    Maths409
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    Quote Originally Posted by Mathstud28 View Post
    I assume you mean expand and combine like factors well...I will expand it for you and you show us the work to combine the factors x^2+3x^2+8\sqrt{3}x+16-[3x^2+8\sqrt{3}x+16]=0
    i'm not sure then.

    how did you manage to get x^2+3x^2+8\sqrt{3}x+16-[3x^2+8\sqrt{3}x+16]=0[/quote]?

    the 3x^2 in the second brackets?

    sorry if i can't see something.
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  4. April 15th 2008, 05:40 PM #4
    Mathstud28
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    Quote Originally Posted by Maths409 View Post
    i'm not sure then.

    how did you manage to get x^2+3x^2+8\sqrt{3}x+16-[3x^2+8\sqrt{3}x+16]=0
    ?

    the 3x^2 in the second brackets?

    sorry if i can't see something.[/quote]
    No problem here is what I did I used the fact that (a+b)^2=a^2+2ab+b^2 and adapting it to (\sqrt{3}x+4)^2=(\sqrt{3}x)^+2\cdot{\sqrt{3}{x}}\c dot{4}+4^2=3x^2+8\sqrt{3}x+16...use the thanks button if youd like
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  5. April 15th 2008, 05:49 PM #5
    Maths409
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    thank you

    is the answer 4x^2 + 4\sqrt{3}x = 0?

    i need to factorise it somehow (so i have 2x terms = 0), can you help me?

    edit: i mean, i need to get 2 x points (on a graph).
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  6. April 15th 2008, 06:05 PM #6
    Mathstud28
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    Ok

    Quote Originally Posted by Maths409 View Post
    thank you

    is the answer 4x^2 + 4\sqrt{3}x = 0?

    i need to factorise it somehow (so i have 2x terms = 0), can you help me?

    edit: i mean, i need to get 2 x points (on a graph).
    I messed up I thought it was the second one squared as well this should be x^2+3x^2+8\sqrt{3}x+16-4\sqrt{3}x-16\Rightarrow{4x^2+4\sqrt{3}x=0}...so factoring we get 4x[x+\sqrt{3}]=0\Rightarrow{x=0,x=-\sqrt{3}}
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