# Thread: Expanding and simplifying

1. ## Expanding and simplifying

can anyone help me expand and simplify this please:

thanks

2. Originally Posted by Maths409
can anyone help me expand and simplify this please:

thanks
I assume you mean expand and combine like factors well...I will expand it for you and you show us the work to combine the factors $\displaystyle x^2+3x^2+8\sqrt{3}x+16-[3x^2+8\sqrt{3}x+16]=0$

3. Originally Posted by Mathstud28
I assume you mean expand and combine like factors well...I will expand it for you and you show us the work to combine the factors $\displaystyle x^2+3x^2+8\sqrt{3}x+16-[3x^2+8\sqrt{3}x+16]=0$
i'm not sure then.

how did you manage to get $\displaystyle x^2+3x^2+8\sqrt{3}x+16-[3x^2+8\sqrt{3}x+16]=0$[/quote]?

the 3x^2 in the second brackets?

sorry if i can't see something.

4. Originally Posted by Maths409
i'm not sure then.

how did you manage to get $\displaystyle x^2+3x^2+8\sqrt{3}x+16-[3x^2+8\sqrt{3}x+16]=0$
?

the 3x^2 in the second brackets?

sorry if i can't see something.[/quote]
No problem here is what I did I used the fact that $\displaystyle (a+b)^2=a^2+2ab+b^2$ and adapting it to $\displaystyle (\sqrt{3}x+4)^2=(\sqrt{3}x)^+2\cdot{\sqrt{3}{x}}\c dot{4}+4^2=3x^2+8\sqrt{3}x+16$...use the thanks button if youd like

5. thank you

is the answer $\displaystyle 4x^2 + 4\sqrt{3}x = 0$?

i need to factorise it somehow (so i have 2x terms = 0), can you help me?

edit: i mean, i need to get 2 x points (on a graph).

6. ## Ok

Originally Posted by Maths409
thank you

is the answer $\displaystyle 4x^2 + 4\sqrt{3}x = 0$?

i need to factorise it somehow (so i have 2x terms = 0), can you help me?

edit: i mean, i need to get 2 x points (on a graph).
I messed up I thought it was the second one squared as well this should be $\displaystyle x^2+3x^2+8\sqrt{3}x+16-4\sqrt{3}x-16\Rightarrow{4x^2+4\sqrt{3}x=0}$...so factoring we get $\displaystyle 4x[x+\sqrt{3}]=0\Rightarrow{x=0,x=-\sqrt{3}}$