Hi guys I have a few questions that I am totally lost on.

1) Write as a single loagrithm: 4lnx - 2(lnx^3 + 4lnx)

2) Solve: 2^x = 3^(x+3)

3) Solve: log(x^2 -1) = 2 + log (x+1)

Thanks in advance!!

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- Apr 15th 2008, 10:46 AM #1

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- Apr 15th 2008, 10:51 AM #2
what have you tried?

here are the rules you need:

2) Solve: 2^x = 3^(x+3)

3) Solve: log(x^2 -1) = 2 + log (x+1)

try them and see what you get

- Apr 15th 2008, 11:09 AM #3

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- Apr 15th 2008, 11:47 AM #4
..................since

...................since

.....................since

.............................since

2) Solve: 2^x = 3^(x+3)

......................use the power rule for logs

.................distribute

...............get all x's to one side

.................factor out the x

.................solve for x

.....................simplify

3) Solve: log(x^2 -1) = 2 + log (x+1)

- Apr 15th 2008, 11:57 AM #5

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- Apr 15th 2008, 12:04 PM #6

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- Apr 15th 2008, 12:06 PM #7