Last Problem, I swear

**bandnerd1892** · April 14th 2008, 06:21 PM

Allright, here's the last problem I need help with, thanks to all those that have helped! Solve:

[(3/x^2)+(1/x)]/[2-(4/5x)]

Thanks! You guys rock!

nerd

**TheEmptySet** · April 14th 2008, 06:27 PM

Originally Posted by bandnerd1892

Allright, here's the last problem I need help with, thanks to all those that have helped! Solve:

[(3/x^2)+(1/x)]/[2-(4/5x)]

Thanks! You guys rock!

nerd

$\frac{\frac{3}{x^2}+\frac{1}{x}}{2-\frac{4}{5x}}$

so we want to multiply both the denominator and numerator by the LCD $5x^2$

$\frac{5x^2}{5x^2} \left( \frac{\frac{3}{x^2}+\frac{1}{x}}{2-\frac{4}{5x}} \right)$

after we distribute we get

$\frac{15+5x}{10x^2-4x}=\frac{5(x+3)}{2x(5x-2)}$

**bandnerd1892** · April 14th 2008, 06:30 PM

thank you!

nerd

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