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Math Help - Last Problem, I swear

  1. #1
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    Last Problem, I swear

    Allright, here's the last problem I need help with, thanks to all those that have helped! Solve:

    [(3/x^2)+(1/x)]/[2-(4/5x)]

    Thanks! You guys rock!

    nerd
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by bandnerd1892 View Post
    Allright, here's the last problem I need help with, thanks to all those that have helped! Solve:

    [(3/x^2)+(1/x)]/[2-(4/5x)]

    Thanks! You guys rock!

    nerd
    \frac{\frac{3}{x^2}+\frac{1}{x}}{2-\frac{4}{5x}}

    so we want to multiply both the denominator and numerator by the LCD 5x^2

    \frac{5x^2}{5x^2} \left( \frac{\frac{3}{x^2}+\frac{1}{x}}{2-\frac{4}{5x}} \right)

    after we distribute we get

    \frac{15+5x}{10x^2-4x}=\frac{5(x+3)}{2x(5x-2)}
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  3. #3
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    thank you!

    nerd
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