Allright, here's the last problem I need help with, thanks to all those that have helped! Solve:

[(3/x^2)+(1/x)]/[2-(4/5x)]

Thanks! You guys rock!

nerd (Hi)

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- Apr 14th 2008, 06:21 PMbandnerd1892Last Problem, I swear
Allright, here's the last problem I need help with, thanks to all those that have helped! Solve:

[(3/x^2)+(1/x)]/[2-(4/5x)]

Thanks! You guys rock!

nerd (Hi) - Apr 14th 2008, 06:27 PMTheEmptySet
$\displaystyle \frac{\frac{3}{x^2}+\frac{1}{x}}{2-\frac{4}{5x}}$

so we want to multiply both the denominator and numerator by the LCD $\displaystyle 5x^2$

$\displaystyle \frac{5x^2}{5x^2} \left( \frac{\frac{3}{x^2}+\frac{1}{x}}{2-\frac{4}{5x}} \right)$

after we distribute we get

$\displaystyle \frac{15+5x}{10x^2-4x}=\frac{5(x+3)}{2x(5x-2)}$ - Apr 14th 2008, 06:30 PMbandnerd1892
thank you!

nerd (Rofl)