# Last Problem, I swear

• April 14th 2008, 06:21 PM
bandnerd1892
Last Problem, I swear
Allright, here's the last problem I need help with, thanks to all those that have helped! Solve:

[(3/x^2)+(1/x)]/[2-(4/5x)]

Thanks! You guys rock!

nerd (Hi)
• April 14th 2008, 06:27 PM
TheEmptySet
Quote:

Originally Posted by bandnerd1892
Allright, here's the last problem I need help with, thanks to all those that have helped! Solve:

[(3/x^2)+(1/x)]/[2-(4/5x)]

Thanks! You guys rock!

nerd (Hi)

$\frac{\frac{3}{x^2}+\frac{1}{x}}{2-\frac{4}{5x}}$

so we want to multiply both the denominator and numerator by the LCD $5x^2$

$\frac{5x^2}{5x^2} \left( \frac{\frac{3}{x^2}+\frac{1}{x}}{2-\frac{4}{5x}} \right)$

after we distribute we get

$\frac{15+5x}{10x^2-4x}=\frac{5(x+3)}{2x(5x-2)}$
• April 14th 2008, 06:30 PM
bandnerd1892
thank you!

nerd (Rofl)