For all positive real numbers a,b,c prove that

$\displaystyle \frac {a}{b+c} +$ $\displaystyle \frac {b}{c+a}+$ $\displaystyle \frac {c}{a+b}$$\displaystyle \geq 3/2$

I applied AM-GM but no luck.

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- Jun 14th 2006, 09:46 PMmalaygoelProof of inequality
For all positive real numbers a,b,c prove that

$\displaystyle \frac {a}{b+c} +$ $\displaystyle \frac {b}{c+a}+$ $\displaystyle \frac {c}{a+b}$$\displaystyle \geq 3/2$

I applied AM-GM but no luck.