1. ## Help Simplifying!

I need help with this. The problem needs to be simplified and I'm confused:

ln [(e^5x)/x(x^4+1)]

Thanks!

nerd :P

2. ## Ok

Originally Posted by bandnerd1892
I need help with this. The problem needs to be simplified and I'm confused:

ln [(e^5x)/x(x^4+1)]

Thanks!

nerd :P
Well Bandnerd...I am going to assume that this is yoru problem $\displaystyle \ln\bigg[\frac{e^{5x}}{x(x^4+1)}\bigg]$...if so then we begin with this $\displaystyle ln(e^{5x})-ln(x(x^4+1))$ due to the fact that the quotient of a log is the difference of the individual logs...next we have $\displaystyle 5x-[ln(x)+ln(x^4+1)]$ this was done using the fact that $\displaystyle \ln(u(x))$ and $\displaystyle e^{u(x)}$ are inverses and using the fact that the products on the interior of a log can be split into the addition of the logs....next we just have to distribute the - to get $\displaystyle ln\bigg[\frac{e^{5x}}{x(x^4+1)}\bigg]=5x-ln(x)-ln(x^4+1)$

3. Thankyou so much! Now it seems simple of course, but oh well. Thank you so much for your help!

nerd

4. Originally Posted by bandnerd1892
Thankyou so much! Now it seems simple of course, but oh well. Thank you so much for your help!

nerd
No problem