I need help with this. The problem needs to be simplified and I'm confused:
ln [(e^5x)/x(x^4+1)]
Thanks!
nerd :P
Well Bandnerd...I am going to assume that this is yoru problem $\displaystyle \ln\bigg[\frac{e^{5x}}{x(x^4+1)}\bigg]$...if so then we begin with this $\displaystyle ln(e^{5x})-ln(x(x^4+1))$ due to the fact that the quotient of a log is the difference of the individual logs...next we have $\displaystyle 5x-[ln(x)+ln(x^4+1)]$ this was done using the fact that $\displaystyle \ln(u(x))$ and $\displaystyle e^{u(x)}$ are inverses and using the fact that the products on the interior of a log can be split into the addition of the logs....next we just have to distribute the - to get $\displaystyle ln\bigg[\frac{e^{5x}}{x(x^4+1)}\bigg]=5x-ln(x)-ln(x^4+1)$