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Math Help - Homework HELP!! 3 problems!

  1. #1
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    Homework HELP!! 3 problems!

    I have three problems that I can't seem to figure out for my homework this week. I basically just can't grasp how to do these.

    1. F = C + 32 for C

    2. (this has to be written in a+bi form)

    3. 1/4

    Any help would be greatly appreciated!!
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  2. #2
    Super Member angel.white's Avatar
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    We can't see your exam images, host them here: ImageShack® - Image Hosting
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  3. #3
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    Better yet on the first one:

    F= 9/5 C +32 for C
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  4. #4
    MHF Contributor Mathstud28's Avatar
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    Ok

    Quote Originally Posted by Kaleid20 View Post
    Better yet on the first one:

    F= 9/5 C +32 for C
    If you mean solve it then you would have F-32=\frac{9c}{5}\Rightarrow{\frac{5(F-32)}{9}}=C? if that is what you are asking
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  5. #5
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    The 2nd was:
    z^2+13z+36/z^2+17z+72 divided by z^2+4z/z^2+6z-16

    I hope that is understood. Sorry I'm just not computer savvy enough to put it in as a picture.
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  6. #6
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by Kaleid20 View Post
    The 2nd was:
    z^2+13z+36/z^2+17z+72 divided by z^2+4z/z^2+6z-16

    I hope that is understood. Sorry I'm just not computer savvy enough to put it in as a picture.
    you can factor this into \frac{(x+9)(x+4)}{(x+9)(x+8)}\Rightarrow{\frac{x+4  }{x+8}} and the second one can be reduced to x\cdot\frac{x+4}{x^2+6x-16} now just divide
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