The Quadratic Formula Explained says:
So, while factoring may not always be successful, the Quadratic Formula can always find the solution.
I'm trying to use the Quadratic Formula to solve but my is much bigger than my so everything under the radical evaulates to a negative number. How can I solve this?
If one sketches the quadratic function, one can see that graph of the function does not at any point intersect x-axis thus there is no real zero. However, for polynom of degree 2 there must neccesarily be two zeros. Because they are not real, they must be complex, which I guess in your case is not neccesary to calculate.