Determine the values of reals numbers x and y such that
(c - 3yi)(4 + i) = 10 - 23i
Hello,Originally Posted by norivea
expand the LHS of your equation. You'll get:
4c-12yi+ic+3y=10-23i
Rearrange into real terms and imaginary terms. You get:
4c+3y=10
ci-12yi=-23i That means: c-12y=-23
Solve this system of linear equations for c and y and you'll get
c = 1
y = 2
Greetings
EB