1. ## average problem

The average of x, 1, 2, 3 is 4, find the average of x, 1 and 2.

my answer was 3 is it correct ?

2. Not quite. Can you show your work so that we can pinpoint any errors you have made? To start, you know the average is 4. So, the sum of all the numbers divided by the number of numbers is equal to 4:

$4 = \frac{x + 1 + 2 + 3}{4}$

You want to find the average of x, 1, and 2 (the sum of these numbers divided by 3 since there are 3 numbers now):

$\mbox{Average} = \frac{x + 1 + 2}{3}$

Can you think of a way to use the first equation to get the average in the second equation?

3. Hello,

If the average of x, 1, 2 and 3 is 4, you can write :

$\frac{x+1+2+3}{4}=4$ (1)

And you're looking for $\frac{x+1+2}{3}$

From (1), we have : $x+1+2+3=16$

So $x+1+2=13$

Then $\underbrace{\frac{x+1+2}{3}}_{\text{average \ of \ x, \ 1, \ 2}}=\frac{13}{3}$

4. Originally Posted by sri340
The average of x, 1, 2, 3 is 4, find the average of x, 1 and 2.

my answer was 3 is it correct ?
Their average is 4 so their sum is 16, the sum is x+6, so x=10.

The average of 10, 1 and 2 is 13/3

RonL

5. Hello, sri340

The average of x, 1, 2, 3 is 4.
Find the average of x, 1 and 2.

my answer was 3 is it correct ? . . . . no
Are you sure you know what an average is?

"The average of x, 1, 2, 3 is 4."

This means: . $\frac{x + 1 + 2 + 3}{4} \:=\:4$

. . Hence: . $x + 1 + 2 + 3 \:=\:16\quad\Rightarrow\quad x + 1 + 2 \:=\:13$

Divide by 3: . $\frac{x + 1 + 2}{3} \:=\:\frac{13}{3}$

. . Therefore, the average of $x,1,2\text{ is: }\:\frac{13}{3}$

6. ## The average of x, 1, 2, 3 is 4, find the average of x, 1 and 2.

average of x 1 2 3 x+1+2+3/4 = 6+x/4 which is equal to 4

then x+6 =16 x= 16-6 = 10

sub x value in average of x, 1 and 2 = 10+1+2/3 = 13/3= 4.3

is it correct?