Results 1 to 2 of 2

Math Help - Tricky word problem..

  1. #1
    Junior Member
    Joined
    Apr 2008
    Posts
    30

    Tricky word problem..

    The perimeter of a rectangle equals one and a half times its area. Express the length of the rectangle in terms of the width (use variable "w" for width).
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member topher0805's Avatar
    Joined
    Jan 2008
    From
    Vancouver
    Posts
    336
    P=2l + 2w

    A=lw

    P=\frac {3A}{2}

    Therefore:

    P=\frac {3lw}{2}

    And:

    2l + 2w=\frac {3lw}{2}

    4l + 4w=3lw

    4w=3lw-4l

    <br />
4w=l(3w-4)

    <br />
l=\frac {4w}{3w-4}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Tricky Word Problem
    Posted in the Calculus Forum
    Replies: 3
    Last Post: June 1st 2010, 12:54 PM
  2. Tricky word problem
    Posted in the Advanced Math Topics Forum
    Replies: 8
    Last Post: January 27th 2010, 06:38 PM
  3. tricky word problem...
    Posted in the Calculus Forum
    Replies: 1
    Last Post: December 17th 2009, 08:11 PM
  4. Tricky Word Problem
    Posted in the Algebra Forum
    Replies: 1
    Last Post: January 25th 2009, 09:25 AM
  5. Tricky word problem
    Posted in the Algebra Forum
    Replies: 6
    Last Post: July 11th 2007, 05:49 PM

Search Tags


/mathhelpforum @mathhelpforum