In a line:

u=nv+nln(theta)

(y=mx+b, n and theta are constants, v=x, u=y)

u = -3.89

v = 0

or

u=-1.9

v=0.693

How can I isolate and find either n or theta?

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- Apr 8th 2008, 08:28 PMtheowneQuick algebra question
In a line:

u=nv+nln(theta)

(y=mx+b, n and theta are constants, v=x, u=y)

u = -3.89

v = 0

or

u=-1.9

v=0.693

How can I isolate and find either n or theta? - Apr 8th 2008, 10:13 PMo_O
Just write it out ;)

$\displaystyle -3.89 = n \cdot 0 + n \ln \theta$

$\displaystyle -3.89 = {\color{blue}n \ln \theta}$

$\displaystyle -1.9 = 0.693 n + {\color{blue}n\ln \theta}$